Lessons

Eamcet Chemistry
1st Year : Unit 1.4 (Basics & Concepts) - Stoichiometric Calculations

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Q.

The weight of calcium carbonate required to produce carbondioxide that is sufficient for conversion of one 0.1 mole sodium carbonate to sodium bicarbonate is

View Answer

Correct choice: B

Explanation:

The balanced equation for conversion of sodium carbonate to sodium bicarbonate is
Na2CO3 + H2O + CO2 → 2NaHCO3
1 mole of Na2CO3 requires 1 mole i.e 44gm of CO2
Carbondioxide required for 0.1 mole of Na2CO3 = 4.4 grams
The balanced equation for the decomposition of calcium carbonate is
CaCO3 ¬¬→ CaO + CO2
1 mole i.e 44gm of CO2 given by 1 mole i.e 100 grams of CaCO3
The weight of calcium carbonate to produce the required 4.4 grms carbondioxide
=(4.4X100/44)=10gms
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